16y^2-8y+1=

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Solution for 16y^2-8y+1= equation:


Simplifying
16y2 + -8y + 1 = 0

Reorder the terms:
1 + -8y + 16y2 = 0

Solving
1 + -8y + 16y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(1 + -4y)(1 + -4y) = 0

Subproblem 1

Set the factor '(1 + -4y)' equal to zero and attempt to solve: Simplifying 1 + -4y = 0 Solving 1 + -4y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -4y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -4y = 0 + -1 -4y = 0 + -1 Combine like terms: 0 + -1 = -1 -4y = -1 Divide each side by '-4'. y = 0.25 Simplifying y = 0.25

Subproblem 2

Set the factor '(1 + -4y)' equal to zero and attempt to solve: Simplifying 1 + -4y = 0 Solving 1 + -4y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -4y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -4y = 0 + -1 -4y = 0 + -1 Combine like terms: 0 + -1 = -1 -4y = -1 Divide each side by '-4'. y = 0.25 Simplifying y = 0.25

Solution

y = {0.25, 0.25}

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